Tentukan hp dari :
2x² + 6x - 7 = 0
[tex] \\ \\ \\ [/tex]
Yang ngasal aku wojakin
Jawaban:
Persamaan kuadrat
[tex] {2x}^{2} + 6x - 7 = 0[/tex]
[tex] {2x}^{2} + 6x = 7[/tex]
[tex] ({2x}^{2} + 6x = 7) \div 2[/tex]
[tex] {x}^{2} + 3x = \frac{7}{2} [/tex]
[tex] {x}^{2} + 3x + {( \frac{3}{2} )}^{2} = \frac{7}{2} + {( \frac{3}{2} )}^{2} [/tex]
[tex] {x}^{2} + 3x + \frac{9}{4} = \frac{7}{2} + \frac{9}{4} [/tex]
[tex] {x}^{2} + 3x + \frac{9}{4} = \frac{14}{4} + \frac{9}{4} [/tex]
[tex] {x}^{2} + 3x + \frac{9}{4} = \frac{23}{4} [/tex]
[tex] {(x + \frac{3}{2} )}^{2} = ± \frac{23}{4} [/tex]
[tex]x + \frac{3}{2} = ± \sqrt{ \frac{23}{4} } [/tex]
[tex]x + \frac{3}{2} = ± \frac{ \sqrt{23} }{2} [/tex]
[tex]x = ± \frac{ \sqrt{23} }{2} - \frac{3}{2} [/tex]
[tex]x1 = \frac{ - 3 + \sqrt{23} }{2} [/tex]
[tex]x2 = \frac{ - 3 - \sqrt{23} }{2} [/tex]
HP = {-3+√23/2. , -3-√23/2}
Dulu Kita Sahabat
Penjelasan dengan langkah-langkah:
[tex]2 {x}^{2} + 6x - 7 = 0[/tex]
[tex]x = \frac{ - 6 + \sqrt{ {6}^{2} - 4.2( - 7) } }{2.2} [/tex]
[tex]x = \frac{ - 6 + 2 \sqrt{23}}{4} [/tex]
[tex]x = \frac{ - 6 - 2 \sqrt{23} }{4} [/tex]
[tex]x = \frac{ - 3 + \sqrt{23} }{2} [/tex]
[tex]x = \frac{ - 3 - \sqrt{23} }{2} [/tex]
Maka Hp : { [tex] {\frac { - 3 + \sqrt{23} }{2} , \frac{ - 3 - \sqrt{23} }{2} }[/tex] }
[answer.2.content]
